ÄÏÔÀÓÐÊÙɽ
ÊÙɽÓкÃÑÎ
ÊÙɽÓкÃÑÎ
ÊÙɽÎÄ»¯£ºÄÏÔÀÊÇÖйúÎåÔÀÖ®ÊÙɽ£¬£¬£¬£¬£¬£¬ÏòÀ´ÎªÆí¸£¡¢ÇóÊÙ֮ʥµØ£¬£¬£¬£¬£¬£¬¸£ÊÙÎÄ»¯Ô´Ô¶Á÷³¤¡£¡£¡£¡£Ê«ÏÉÀî°×Ê«ÔÆ£º“ºâɽ²Ô²ÔÈë×ÏÚ¤£¬£¬£¬£¬£¬£¬Ï¿´Äϼ«ÀÏÈËÐÇ”¡£¡£¡£¡£×ÔÈ»Ìõ¼þºÜÊÇÊʺÏÈËÃÇÑøÉú½¡Éí¡¢ÒæÊÙÑÓÄê¡£¡£¡£¡£
¾«Öƹ¤ÒÕ£º²úÆ·ÖÊÁϲÉ×ÔµØÏÂÓëÄÏÔÀºâɽһÂöÏà³ÐµÄ×ÔÈ»ÑÒÑοó¶Î£¬£¬£¬£¬£¬£¬¸¨ÒÔ¹ú¼ÊÏȽøµÄÏÖ´úÕæ¿ÕÖÆÑι¤ÒÕ¾«Öƶø³É¡£¡£¡£¡£Á£Á£¾«Ñ¡£¡£¡£¡£¬£¬£¬£¬£¬£¬¿Å¿ÅÕé´¿¡£¡£¡£¡£
²»Ìí¼ÓÈκÎʳÑο¹½á¼Á£ºÁ£¶È0.45-0.85mm£¬£¬£¬£¬£¬£¬²»Ìí¼ÓʳÑο¹½á¼Á¡£¡£¡£¡£
ÄÆ¼ØÆ½ºâ¡¢µÍÄÆ¸ü¿µ½¡£ºÒÔÂÈ»¯¼ØÈ¡´ú²¿·ÖÂÈ»¯ÄÆ£¬£¬£¬£¬£¬£¬ÓÐÖúÓÚÉÅʳ¼õÄÆ¡£¡£¡£¡£Ã»ÓÐÌí¼ÓµâÓªÑøÇ¿»¯¼Á£¬£¬£¬£¬£¬£¬ÊÊºÏ¸ßµâµØÇøºÍ×ñÒ½Öö²»ÏàÒËʳÓõâÑεÄÈËȺʳÓᣡ£¡£¡£
Á¬Ã¦¹ºÖÃ
ÍÆ¼ö²úÆ·
ÓÐÁèÔÆÖ®Ö¾£¬£¬£¬£¬£¬£¬ÊǰÙľ֮³¤¡£¡£¡£¡£¼È´ú±íÁËÖлªÃñ×åµÄ¼áÈͲ»°Î¡¢Æ·Öʸ߽àµÄ¾«ÉñÇé½Ú£¬£¬£¬£¬£¬£¬ÓÖÌåÏÖÁ˸ü¸ßµÄ¾³½ç¡¢¸ü¸ßµÄ±ê×¼¡£¡£¡£¡£
ÓÐÁèÔÆÖ®Ö¾£¬£¬£¬£¬£¬£¬ÊǰÙľ֮³¤¡£¡£¡£¡£¼È´ú±íÁËÖлªÃñ×åµÄ¼áÈͲ»°Î¡¢Æ·Öʸ߽àµÄ¾«ÉñÇé½Ú£¬£¬£¬£¬£¬£¬ÓÖÌåÏÖÁ˸ü¸ßµÄ¾³½ç¡¢¸ü¸ßµÄ±ê×¼¡£¡£¡£¡£
ÔÚÏßѯ¼Û
* ×¢ÖØ: ÇëÎñ±Ø×¼È·ÌîдÐÅÏ¢²¢¼á³ÖÏàͬÁ÷ͨ£¬£¬£¬£¬£¬£¬ÎÒÃǻᾡ¿ìÓëÄúÁªÏµ